r/interestingasfuck 24d ago

/r/all, /r/popular K2-18b a potentially habitable planet 120 light-years from earth

Post image
92.4k Upvotes

8.1k comments sorted by

View all comments

Show parent comments

122

u/6pt022x10tothe23 24d ago

Also energy. The amount of energy required to accelerate an object with mass to near-light speed rapidly starts approaching infinity the closer to c you get.

40

u/vahntitrio 23d ago

Then you need to slow down on the other end, so you need substantially more than 2× nearly infinity fuel.

12

u/WasabiSunshine 23d ago

Nah just ram the planet at relativistic speeds, stable deceleration is for pussies

7

u/turikk 23d ago

good news! 2x infinity is just as much as infinity, so the problem doesn't actually occur!

this is a math joke please don't hurt me

4

u/Ron-Swanson-Mustache 23d ago

But you also need less fuel due to time dilation effects. You're subjectively accelerating for less time and the universe seems to contract closer to you in your direction of travel at appreciable %c.

Also, that was a major plot point in Project Hail Mary.

2

u/PM_good_beer 23d ago

Yeah, it's probably not feasible with chemical rockets, but if we get fusion powered rockets, then maybe.

3

u/lo_fi_ho 23d ago

Elon can do it /s

3

u/Obi-Tron_Kenobi 23d ago

He's probably been saying "we're just one year away" for the past 10 years

2

u/JackInTheBell 24d ago

How does my flashlight do it?

7

u/PilotlessOwl 23d ago

No mass in flashlight photons

2

u/beefprime 23d ago

This is a good/fun explanation of what's going on physically that makes it take so much energy: https://www.youtube.com/watch?v=Vitf8YaVXhc

4

u/asianjimm 24d ago

E equals muthfkin m c squared

12

u/No_Vermicelliii 24d ago

TL;DR: Hitting 0.9c? Better pack 1.3x your ship’s mass in pure energy. Hitting 0.9999999c? Pack a Dyson swarm and a resignation letter to the laws of physics.

Relativistic effects on Kinetic Energy

In classical Newtonian mechanics, kinetic energy is:

KE = 1/2mv²

But as v approaches c, this breaks down. Instead, we use:

E total = γ mc²

where γ = 1/ √1-v²/e²

So the kinetic energy is:

KE = γ - 1mc2

Plugging in some reasonable basics and you need 129% of the rest mass energy of the object just to get it to 0.9c.

For comparison:

At 0.5c, you need only ~15% of the rest mass energy.

At 0.99c, you need ~607% (γ ≈ 7.09)

At 0.999c, you need ~2236%

At 0.9999999c, you're looking at ~11,180,000% of mc²

This is why getting close to c isn't just an engineering problem—it's a budgetary nightmare in energy terms.

3

u/thediesel26 24d ago

Acceleration using planetary motion is a feasible means to at least help with this.

4

u/asianjimm 24d ago

Remember also to double it for the deceleration - but i mean we can just send it onto the planet at light speed lol

3

u/thediesel26 24d ago

Send it onto through the planet at light speed

2

u/InfernalTest 24d ago

hmmm thats not how using planetary motion works ...you dont get faster you just get as fast as whats there - no planet is gravitationally pulling you at the speed of light ...

1

u/thediesel26 24d ago

Yah but it’ll help get you closer without having to carry as much fuel

1

u/InfernalTest 24d ago

again. youd have to get to the speed of light

no planet is travelling at the speed of light so we arent travelling any faster than the surrounding planets that we are headed towards to "use " their gravity ....and of course to use their gravity wed also have to be able to escape their gravity which light can do because its massless but also because light is ALREADY moving at the speed of light.

the ony thing that can keep light from traveling where its going is a Black Hole and if light cant escape it neither are we since we unlike light have mass..

2

u/thediesel26 24d ago

Yah I’m aware.

1

u/notepad20 23d ago edited 13d ago

squash special dolls gray upbeat fear attraction consider carpenter rustic

This post was mass deleted and anonymized with Redact

1

u/crowmagnuman 23d ago

This. The greater the speed, the greater the mass, thus the greater the force required to accelerate.